Upstream-Status: Backport Signed-off-by: Khem Raj From patchwork Fri Apr 19 09:34:49 2013 Content-Type: text/plain; charset="utf-8" MIME-Version: 1.0 Content-Transfer-Encoding: 7bit Subject: [ARM] Fix PR56797 Date: Thu, 18 Apr 2013 23:34:49 -0000 From: Greta Yorsh X-Patchwork-Id: 237891 Message-Id: <000801ce3ce1$23fbdd60$6bf39820$@yorsh@arm.com> To: "GCC Patches" Cc: , "Richard Earnshaw" , "Ramana Radhakrishnan" Fix PR56797 http://gcc.gnu.org/bugzilla/show_bug.cgi?id=56797 The problem is that peephole optimizer thinks it can generate an ldm, but the pattern for ldm no longer matches, because after r188738 it requires that if one of the destination registers is SP then the base register must be SP, and it's not SP in the test case. The test case fails on armv5t but doesn't fail on armv6t2 or armv7-a because peephole doesn't trigger there (because there is a different epilogue sequence). It looks like a latent problem for other architecture or CPUs. This patch adds this condition to the peephole optimizer. No regression on qemu for arm-none-eabi and fixes the test reported in the PR. I couldn't minimize the test sufficiently to include it in the testsuite. Ok for trunk? Thanks, Greta gcc/ 2013-04-18 Greta Yorsh PR target/56797 * config/arm/arm.c (load_multiple_sequence): Require SP as base register for loads if SP is in the register list. diff --git a/gcc/config/arm/arm.c b/gcc/config/arm/arm.c index d00849c..60fef78 100644 --- a/gcc/config/arm/arm.c +++ b/gcc/config/arm/arm.c @@ -10347,6 +10347,13 @@ load_multiple_sequence (rtx *operands, int nops, int *regs, int *saved_order, || (i != nops - 1 && unsorted_regs[i] == base_reg)) return 0; + /* Don't allow SP to be loaded unless it is also the base + register. It guarantees that SP is reset correctly when + an LDM instruction is interruptted. Otherwise, we might + end up with a corrupt stack. */ + if (unsorted_regs[i] == SP_REGNUM && base_reg != SP_REGNUM) + return 0; + unsorted_offsets[i] = INTVAL (offset); if (i == 0 || unsorted_offsets[i] < unsorted_offsets[order[0]]) order[0] = i;