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-rw-r--r--meta/recipes-extended/shadow/files/CVE-2023-4641.patch147
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diff --git a/meta/recipes-extended/shadow/files/CVE-2023-4641.patch b/meta/recipes-extended/shadow/files/CVE-2023-4641.patch
deleted file mode 100644
index 1fabfe928e..0000000000
--- a/meta/recipes-extended/shadow/files/CVE-2023-4641.patch
+++ /dev/null
@@ -1,147 +0,0 @@
-From 25dbe2ce166a13322b7536ff2f738786ea2e61e7 Mon Sep 17 00:00:00 2001
-From: Alejandro Colomar <alx@kernel.org>
-Date: Sat, 10 Jun 2023 16:20:05 +0200
-Subject: [PATCH] gpasswd(1): Fix password leak
-
-How to trigger this password leak?
-~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-
-When gpasswd(1) asks for the new password, it asks twice (as is usual
-for confirming the new password). Each of those 2 password prompts
-uses agetpass() to get the password. If the second agetpass() fails,
-the first password, which has been copied into the 'static' buffer
-'pass' via STRFCPY(), wasn't being zeroed.
-
-agetpass() is defined in <./libmisc/agetpass.c> (around line 91), and
-can fail for any of the following reasons:
-
-- malloc(3) or readpassphrase(3) failure.
-
- These are going to be difficult to trigger. Maybe getting the system
- to the limits of memory utilization at that exact point, so that the
- next malloc(3) gets ENOMEM, and possibly even the OOM is triggered.
- About readpassphrase(3), ENFILE and EINTR seem the only plausible
- ones, and EINTR probably requires privilege or being the same user;
- but I wouldn't discard ENFILE so easily, if a process starts opening
- files.
-
-- The password is longer than PASS_MAX.
-
- The is plausible with physical access. However, at that point, a
- keylogger will be a much simpler attack.
-
-And, the attacker must be able to know when the second password is being
-introduced, which is not going to be easy.
-
-How to read the password after the leak?
-~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-
-Provoking the leak yourself at the right point by entering a very long
-password is easy, and inspecting the process stack at that point should
-be doable. Try to find some consistent patterns.
-
-Then, search for those patterns in free memory, right after the victim
-leaks their password.
-
-Once you get the leak, a program should read all the free memory
-searching for patterns that gpasswd(1) leaves nearby the leaked
-password.
-
-On 6/10/23 03:14, Seth Arnold wrote:
-> An attacker process wouldn't be able to use malloc(3) for this task.
-> There's a handful of tools available for userspace to allocate memory:
->
-> - brk / sbrk
-> - mmap MAP_ANONYMOUS
-> - mmap /dev/zero
-> - mmap some other file
-> - shm_open
-> - shmget
->
-> Most of these return only pages of zeros to a process. Using mmap of an
-> existing file, you can get some of the contents of the file demand-loaded
-> into the memory space on the first use.
->
-> The MAP_UNINITIALIZED flag only works if the kernel was compiled with
-> CONFIG_MMAP_ALLOW_UNINITIALIZED. This is rare.
->
-> malloc(3) doesn't zero memory, to our collective frustration, but all the
-> garbage in the allocations is from previous allocations in the current
-> process. It isn't leftover from other processes.
->
-> The avenues available for reading the memory:
-> - /dev/mem and /dev/kmem (requires root, not available with Secure Boot)
-> - /proc/pid/mem (requires ptrace privileges, mediated by YAMA)
-> - ptrace (requires ptrace privileges, mediated by YAMA)
-> - causing memory to be swapped to disk, and then inspecting the swap
->
-> These all require a certain amount of privileges.
-
-How to fix it?
-~~~~~~~~~~~~~~
-
-memzero(), which internally calls explicit_bzero(3), or whatever
-alternative the system provides with a slightly different name, will
-make sure that the buffer is zeroed in memory, and optimizations are not
-allowed to impede this zeroing.
-
-This is not really 100% effective, since compilers may place copies of
-the string somewhere hidden in the stack. Those copies won't get zeroed
-by explicit_bzero(3). However, that's arguably a compiler bug, since
-compilers should make everything possible to avoid optimizing strings
-that are later passed to explicit_bzero(3). But we all know that
-sometimes it's impossible to have perfect knowledge in the compiler, so
-this is plausible. Nevertheless, there's nothing we can do against such
-issues, except minimizing the time such passwords are stored in plain
-text.
-
-Security concerns
-~~~~~~~~~~~~~~~~~
-
-We believe this isn't easy to exploit. Nevertheless, and since the fix
-is trivial, this fix should probably be applied soon, and backported to
-all supported distributions, to prevent someone else having more
-imagination than us to find a way.
-
-Affected versions
-~~~~~~~~~~~~~~~~~
-
-All. Bug introduced in shadow 19990709. That's the second commit in
-the git history.
-
-Fixes: 45c6603cc86c ("[svn-upgrade] Integrating new upstream version, shadow (19990709)")
-
-CVE: CVE-2023-4641
-Upstream-Status: Backport [https://github.com/shadow-maint/shadow/commit/65c88a43a23c2391dcc90c0abda3e839e9c57904]
-
-Reported-by: Alejandro Colomar <alx@kernel.org>
-Cc: Serge Hallyn <serge@hallyn.com>
-Cc: Iker Pedrosa <ipedrosa@redhat.com>
-Cc: Seth Arnold <seth.arnold@canonical.com>
-Cc: Christian Brauner <christian@brauner.io>
-Cc: Balint Reczey <rbalint@debian.org>
-Cc: Sam James <sam@gentoo.org>
-Cc: David Runge <dvzrv@archlinux.org>
-Cc: Andreas Jaeger <aj@suse.de>
-Cc: <~hallyn/shadow@lists.sr.ht>
-Signed-off-by: Alejandro Colomar <alx@kernel.org>
-Signed-off-by: Xiangyu Chen <xiangyu.chen@windriver.com>
----
- src/gpasswd.c | 1 +
- 1 file changed, 1 insertion(+)
-
-diff --git a/src/gpasswd.c b/src/gpasswd.c
-index 5983f787..2d8869ef 100644
---- a/src/gpasswd.c
-+++ b/src/gpasswd.c
-@@ -896,6 +896,7 @@ static void change_passwd (struct group *gr)
- strzero (cp);
- cp = getpass (_("Re-enter new password: "));
- if (NULL == cp) {
-+ memzero (pass, sizeof pass);
- exit (1);
- }
-
---
-2.34.1
-